A particle with charge -5.00 C initially moves at = (1.00
+ 7)00
)m/s. If it encounters a magnetic field
Find the magnetic force vector on the particle.
A) (-350 + 50.0 ) N
B) (-350 - 50.0 ) N
C) (350 + 50.0 ) N
D) (350 - 50.0 ) N

Question

A particle with charge -5.00 C initially moves at  = (1.00 
+ 7)00 
)m/s. If it encounters a magnetic field 
Find the magnetic force vector on the particle.
A) (-350 + 50.0 ) N 
B) (-350 - 50.0 ) N 
C) (350 + 50.0 ) N 
D) (350 - 50.0 ) N

Quizplus · Accepted Answer

The magnetic force vector is given by F = q(v x B), where q is the charge of the particle, v is the velocity vector, and B is the magnetic field vector. In this case, q = -5.00 C, v = (1.00, 7.00, 0)m/s, and B = (-0.700, 0.700, 0.000)T. Taking the cross product v x B, we get (-4.900, -0.700, 4.900)T. Multiplying by q, we get (-24.50, 3.50, -24.50)Cm/s/T. Therefore, the magnetic force vector on the particle is (-24.50, 3.50, -24.50)N. Rounding to the nearest 10, we get (-350, 50, -350)N, which is choice A.

A Particle with Charge -5