You are designing a generator to have a maximum emf of 8.0 V.If the generator coil has 200 turns and a cross-sectional area of 0.030 m²,what should be the frequency of the generator in a uniform magnetic field of 0.030 T? A) 7.1 Hz B) 7.5 Hz C) 8.0 Hz D) 22 Hz E) 44 Hz

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Quizplus · Accepted Answer

The maximum emf (E_max) generated by a coil in a magnetic field can be calculated using the formula: E_max = NABωsin(θ), where N is the number of turns, A is the area, B is the magnetic field strength, ω is the angular frequency (ω = 2πf, where f is the frequency), and θ is the angle between the magnetic field and the normal to the coil. Since the maximum emf occurs when sin(θ) = 1, the equation simplifies to E_max = NABω. Solving for frequency (f), we get f = E_max / (2πNAB).Given: E_max = 8.0 V, N = 200 turns, A = 0.030 m^2, B = 0.030 T, we find:f = 8.0 / (2π * 200 * 0.030 * 0.030) = 7.1 Hz.

You Are Designing a Generator to Have a Maximum Emf