What is the self-inductance of a solenoid 30.0 cm long having 100 turns of wire and a cross-sectional area of 1.00 × 10^-4 m²? (μ₀ = 4π × 10^-7 T • m/A) A) 4.19 nH B) 4.19 pH C) 4.19 µH D) 4.19 mH E) 4.19 H

Question

Quizplus · Accepted Answer

The formula for the self-inductance of a solenoid is L = μN²Aℓ / 2ℓ, where μ is the permeability of free space, N is the number of turns, A is the cross-sectional area, and ℓ is the length of the solenoid. Plugging in the given values:

L = (4π × 10^-7 T·m/A) * (100)^2 * (1.00 × 10^-4 m^2) / (2 * 0.30 m) 
L = 4.19 µH

Therefore, the best choice is C, 4.19 µH.

What Is the Self-Inductance of a Solenoid 30