A car starts from rest and accelerates at a steady 6.00 m/s².How far does it travel in the first 3.00 s? A)9.00 m B)18.0 m C)27.0 m D)36.0 m E)54.0 m

Question

Quizplus · Accepted Answer

The distance traveled by a car starting from rest and accelerating at a steady rate can be calculated using the equation:

d = (1/2)at^2

Where d is the distance traveled, a is the acceleration, and t is the time.

In this case, the acceleration is 6.00 m/s^2 and the time is 3.00 s.

Plugging in these values, we get:

d = (1/2)(6.00 m/s^2)(3.00 s)^2
d = (1/2)(6.00 m/s^2)(9.00 s^2)
d = 27.0 m

Therefore, the car travels 27.0 m in the first 3.00 s. The correct answer is C.

A Car Starts from Rest and Accelerates at a Steady