A stone is thrown with an initial upward velocity of 7.0 m/s.If we take upward as the positive direction,what is the velocity of the stone after 0.50 s,assuming there is no air?
A)2.1 m/s
B)4.9 m/s
C)-2.1 m/s
D)-4.9 m/s
E)0.00 m/s

Question

Quizplus · Accepted Answer

The velocity of the stone after 0.50 s can be calculated using the equation $v = u + at$, where $v$ is the final velocity, $u$ is the initial velocity (7.0 m/s upwards), $a$ is the acceleration due to gravity (-9.8 m/s$^2$ downwards), and $t$ is the time (0.50 s). Substituting the values, we get $v = 7.0 m/s + (-9.8 m/s$^2$) \times 0.50 s = 7.0 m/s - 4.9 m/s = 2.1 m/s$ upwards.

A Stone Is Thrown with an Initial Upward Velocity of 7.0