A ball is thrown straight upward from ground level with a speed of 18 m/s.How much time passes before the ball strikes the ground if we disregard air resistance?
A)3.7 s
B)1.8 s
C)1.1 s
D)0.6 s

Question

Quizplus · Accepted Answer

The time for the ball to reach its highest point can be calculated using the formula $t = \frac{v}{g}$, where $v = 18 \, \text{m/s}$ is the initial velocity and $g = 9.8 \, \text{m/s}^2$ is the acceleration due to gravity. This gives $t = \frac{18}{9.8} \approx 1.84 \, \text{s}$. Since the time to go up is the same as the time to come down, the total time is $2 \times 1.84 \approx 3.7 \, \text{s}$.

A Ball Is Thrown Straight Upward from Ground Level with a Speed