A ball is thrown with an initial velocity of 20 m/s at an angle of 60° above the horizontal.If we can neglect air,what is the horizontal component of its instantaneous velocity at the exact top of its trajectory?
A)10 m/s
B)17 m/s
C)20 m/s
D)zero

Question

Quizplus · Accepted Answer

At the top of its trajectory, the vertical component of the velocity is zero, but the horizontal component remains constant. The horizontal component is given by the initial velocity multiplied by the cosine of the angle: 20 m/s * cos(60°) = 10 m/s.

A Ball Is Thrown with an Initial Velocity of 20