An athlete participates in an interplanetary discus throw competition during an Olympiad that takes place on a planet where the free-fall acceleration is 9.7 m/s².He throws the discus with an initial velocity of 20 m/s at an angle of 60° from the vertical.Neglecting air resistance and the height of the discus at the point of release,what is the range of the discus? A)21 m B)60 m C)36 m D)40 m E)32 m

Question

Quizplus · Accepted Answer

The range of the discus can be found using the equation:
R = (v^2/g) * sin(2θ)
where v is the initial velocity, g is the acceleration due to gravity (9.7 m/s^2 in this case), and θ is the angle of launch (60° in this case).

Plugging in the given values:
R = (20^2/9.7) * sin(2*60)
R = 36.28 m

Therefore, the range of the discus is approximately 36 m, which is closest to option C.

An Athlete Participates in an Interplanetary Discus Throw Competition During