A driver in a $1000 - \mathrm { kg }$ car traveling at $24 \mathrm {~m} / \mathrm { s }$ slams on the brakes and skids to a stop.If the coefficient of friction between the tires and the level road is 0.80,how long will the skid marks be?
A)37 m
B)30 m
C)46 m
D)34 m

Question

Quizplus · Accepted Answer

The length of the skid marks can be calculated using the formula derived from the work-energy principle, where the work done by friction is equal to the change in kinetic energy. The formula is $d = \frac{v^2}{2\mu g}$, where $d$ is the distance (length of skid marks), $v$ is the initial velocity, $\mu$ is the coefficient of friction, and $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$). Plugging in the given values: $d = \frac{(24)^2}{2 \times 0.80 \times 9.8} \approx 37 \, \text{m}$.

A Driver in A 1000−kg1000 - \mathrm { kg }1000−kg Car Traveling At

A Driver in A $1000 - \mathrm { kg }$ Car Traveling At