The mass of the Moon is 7.4 × 10²² kg,its radius is 1.74 × 10³ km,and it has no atmosphere.What is the free-fall acceleration at the surface of the Moon? (G = 6.67 × 10^-11 N ∙ m²/kg²)

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Quizplus · Accepted Answer

The free-fall acceleration on the surface of a celestial body can be calculated using the formula $g = \frac{GM}{r^2}$, where $G$ is the gravitational constant, $M$ is the mass of the body, and $r$ is its radius. Substituting the given values: $G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2$, $M = 7.4 \times 10^{22} \, \text{kg}$, and $r = 1.74 \times 10^6 \, \text{m}$, we find the free-fall acceleration on the Moon's surface to be approximately $1.6 \, \text{m/s}^2$.

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