A traveler pulls on a suitcase strap at an angle 36° above the horizontal.The suitcase is the system.If $555 \mathrm {~J}$ of work are done by the strap while moving the suitcase a horizontal distance of $15 \mathrm {~m}$ what is the tension force that the strap exerts on the suitcase?

Question

Quizplus · Accepted Answer

The work done on the suitcase can be calculated using the formula $W = Fd\cos(\theta)$, where $W$ is the work done, $F$ is the force applied, $d$ is the distance moved, and $\theta$ is the angle of the force with respect to the horizontal direction. Rearranging the formula to solve for $F$ gives $F = \frac{W}{d\cos(\theta)}$. Substituting the given values ($W = 555 \, \mathrm{J}$, $d = 15 \, \mathrm{m}$, $\theta = 36^\circ$) into the formula yields $F = \frac{555}{15\cos(36^\circ)} \approx 46 \, \mathrm{N}$.

A Traveler Pulls on a Suitcase Strap at an Angle 555 J555 \mathrm {~J}555 J

A Traveler Pulls on a Suitcase Strap at an Angle $555 \mathrm {~J}$