An electrical motor spins at a constant $2695.0 \mathrm { rpm }$ If the rotor radius is $7.165 \mathrm {~cm}$ what is the linear acceleration of the edge of the rotor? A)5707 m/s² B)281.6 m/s² C)572,400 m/s² D)28.20 m/s²

Question

Quizplus · Accepted Answer

The linear acceleration $a$ of the edge of the rotor can be calculated using the formula $a = r\omega^2$, where $r$ is the radius of the rotor and $\omega$ is the angular velocity in radians per second. First, convert the rotational speed from rpm to rad/s: $\omega = 2695.0 \times \frac{2\pi}{60} \approx 282.743 \, \text{rad/s}$. Then, with $r = 7.165 \, \text{cm} = 0.07165 \, \text{m}$, the linear acceleration is $a = 0.07165 \times (282.743)^2 \approx 5707 \, \text{m/s}^2$.

An Electrical Motor Spins at a Constant 2695.0rpm2695.0 \mathrm { rpm }2695.0rpm

An Electrical Motor Spins at a Constant $2695.0 \mathrm { rpm }$