A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill,starting from rest.If the angular speed of the disk is 4.27 rad/s at the bottom,how high did it start on the hill?
A)3.57 m
B)2.68 m
C)3.14 m
D)4.28 m

Question

Quizplus · Accepted Answer

The potential energy at the top is converted to translational and rotational kinetic energy at the bottom. Using energy conservation: mgh = 0.5mv^2 + 0.5Iω^2. For a disk, I = 0.5mr^2. Solving for h gives h = 3.57 m.

A Solid Uniform Disk of Diameter 3