A pencil that is 15.7 cm long is released from a vertical position with the eraser end resting on a table.The eraser does not slip as it tips over.Treat the pencil like a uniform rod.What is the angular speed of the pencil just before it hits the table?
A)13.7 rad/s
B)7.23 rad/s
C)3.70 rad/s
D)24.5 rad/s
E)16.8 rad/s

Question

Quizplus · Accepted Answer

The correct answer is A because the angular speed of the pencil just before it hits the table is 13.7 rad/s. This can be calculated using the formula:ω = √(2gh/L)where:ω is the angular speed in radians per secondg is the acceleration due to gravity (9.8 m/s^2)h is the height from which the pencil is released (15.7 cm = 0.157 m)L is the length of the pencil (15.7 cm = 0.157 m)Plugging these values into the formula, we get:ω = √(2 * 9.8 m/s^2 * 0.157 m / 0.157 m)ω = √(19.21 m^2/s^2)ω = 13.7 rad/s

A Pencil That Is 15