The density of material at the center of a neutron star is approximately 1.00 × 10¹⁸ kg/m³.What is the mass of a cube of this material that is $1.76 \mathrm { microns }$ on each side.(One micron is equal to 1.00 × 10^-6 m.)

Question

Quizplus · Accepted Answer

The volume of the cube is:$$V = (1.76 	imes 10^{-6} 	ext{ m})^3 = 5.37 	imes 10^{-18} 	ext{ m}^3$$The mass of the cube is:$$m = ho V = (1.00 	imes 10^{18} 	ext{ kg/m}^3)(5.37 	imes 10^{-18} 	ext{ m}^3) = 5.37 	ext{ kg}$$The closest answer choice is 5.45 kg, which is choice A.

The Density of Material at the Center of a Neutron 1.76microns1.76 \mathrm { microns }1.76microns

The Density of Material at the Center of a Neutron $1.76 \mathrm { microns }$