What is the average translational kinetic energy of an ideal gas at $819 \mathrm {~K} \text { ? }$ The Boltzmann constant is 1.38 × 10^-23 J/K.

Question

Quizplus · Accepted Answer

The average translational kinetic energy of an ideal gas is given by $\frac{3}{2}kT$. Substituting $k = 1.38 \times 10^{-23} \, \text{J/K}$ and $T = 819 \, \text{K}$, the energy is $1.70 \times 10^{-20} \, \text{J}$.

What Is the Average Translational Kinetic Energy of an Ideal 819 K ? 819 \mathrm {~K} \text { ? }819 K ?

What Is the Average Translational Kinetic Energy of an Ideal $819 \mathrm {~K} \text { ? }$