A 500-N object sits on the small piston of a hydraulic machine.The small piston has an area of 2.0 cm².If the large piston has an area of 40 cm²,how much weight can the large piston support? Assume the pistons each have negligible weight. A)25 N B)500 N C)10000 N D)40000 N

Question

Quizplus · Accepted Answer

We can use the formula for hydraulic machines:

F1/A1 = F2/A2

where F1 is the force on the small piston, A1 is the area of the small piston, F2 is the force on the large piston, and A2 is the area of the large piston.

Plugging in the given values, we get:

500 N/2.0 cm^2 = F2/40 cm^2

Solving for F2:

F2 = (500 N/2.0 cm^2) * 40 cm^2

F2 = 10,000 N

Therefore, the large piston can support a weight of 10,000 N.

The correct answer is C) 10,000 N.

A 500-N Object Sits on the Small Piston of a Hydraulic