Motor oil,with a viscosity of 0.25 N ∙ s/m²,is flowing through a tube that has a radius of 5.0 mm and is 25 cm long.The drop in pressure is 300 kPa.What is the volume of oil flowing through the tube per second? A)0.00038 m³/s B)0.025 m³/s C)0.0012 m³/s D)4.7 m³/s E)7.5 m³/s

Question

Quizplus · Accepted Answer

We can use Poiseuille's law to solve for the volume of oil flowing through the tube per second. Q = (πr^4ΔP)/(8ηL) where Q is the volume flow rate, r is the radius of the tube, ΔP is the pressure drop, η is the viscosity, and L is the length of the tube. Plugging in the given values, we get: Q = (π(5.0×10^-3 m)^4(300×10^3 Pa))/(8(0.25 N∙s/m^2)(0.25 m)) Q = 0.0012 m^3/s Therefore, the volume of oil flowing through the tube per second is 0.0012 m^3/s or 0.0012 m³/s, which corresponds to choice C.

Motor Oil,with a Viscosity of 0