If 150 kcal of thermal energy raises the temperature of 2.0 kg of a material by 400 F°,what is the specific heat capacity of the material?

Question

Quizplus · Accepted Answer

We can use the formula:

Q = cmΔT

where Q is the thermal energy, c is the specific heat capacity, m is the mass of the material, and ΔT is the change in temperature.

Substituting the given values:

150 kcal = c x 2.0 kg x 400°F

Simplifying:

c = 150 kcal / (2.0 kg x 400°F)

c = 0.1875 kcal / (kg x °C)

Converting kcal to J and °C to K:

c = 0.1875 x 4184 J / (kg x K)

c = 782.4 J / (kg x K)

c = 0.34 kcal / (kg x °C) (rounded to two significant figures)

Therefore, the specific heat capacity of the material is approximately 0.34 kcal/kg ∙ C°. The closest option is (C).

If 150 Kcal of Thermal Energy Raises the Temperature of 2.0