A 920-g empty iron kettle is put on a stove.How much thermal energy in joules must be transferred to it to raise its temperature form $15.0 ^ { \circ } \mathrm { C }$ to $93.0 ^ { \circ } \mathrm { C } \text { ? }$ The specific heat for iron is 113 cal/kg ∙ C°,and 1 cal = 4.186 J.

Question

Quizplus · Accepted Answer

The correct answer is A because the thermal energy required to raise the temperature of the kettle is given by:Q = mcΔTwhere m is the mass of the kettle, c is the specific heat of iron, and ΔT is the change in temperature.Plugging in the given values, we get:Q = (0.920 kg)(113 cal/kg ∙ C°)(93.0 °C - 15.0 °C)Q = 33,900 J

A 920-G Empty Iron Kettle Is Put on a Stove 15.0∘C15.0 ^ { \circ } \mathrm { C }15.0∘C

A 920-G Empty Iron Kettle Is Put on a Stove $15.0 ^ { \circ } \mathrm { C }$