A 45.0-kg sample of ice is at 0.00° C.How much thermal energy is needed to melt it? For water L_F = 334,000 J/kg and L_V = 2.256 × 10⁶ J/kg.

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Quizplus · Accepted Answer

The amount of thermal energy needed to melt a 45.0-kg sample of ice at 0.00° C can be calculated using the formula Q = m * L, where m is the mass of the ice and L is the latent heat of fusion for water (334,000 J/kg). Thus, Q = 45.0 kg * 334,000 J/kg = 15,030,000 J or 1.50 × 10^7 J (which is equivalent to 15.0 MJ or 1.50 × 10^4 kJ).

A 450-Kg Sample of Ice Is at 0