Thermal energy through the process of heating is added to a 3.0 kg piece of ice at a rate of $636.0 \mathrm {~kW}$ How long will it take for the ice at 0.0° C to melt? For water L_F = 334,000 J/kg and L_V = 2.246 × 10⁶ J/kg.

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Quizplus · Accepted Answer

The energy required to melt the ice can be calculated using the latent heat formula: $Q = mL$, where $m$ is the mass of the ice and $L$ is the latent heat of fusion for water. Given $m = 3.0 \, \text{kg}$ and $L = 334,000 \, \text{J/kg}$, $Q = 3.0 \, \text{kg} \times 334,000 \, \text{J/kg} = 1,002,000 \, \text{J}$. The power $P = 636.0 \, \text{kW} = 636,000 \, \text{W}$, and time $t = Q / P$, so $t = 1,002,000 \, \text{J} / 636,000 \, \text{W} = 1.575 \, \text{s}$, which rounds to approximately 1.6 seconds.

Thermal Energy Through the Process of Heating Is Added to a 3.0