A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110 kPa.How much work is done on the gas during this expansion?

Question

Quizplus · Accepted Answer

The work done on a gas during expansion at constant pressure can be calculated using the formula W = -PΔV, where W is the work done, P is the pressure, and ΔV is the change in volume. Here, ΔV = 65.0 L - 30.0 L = 35.0 L = 35.0 x 10^-3 m^3 (since 1 L = 10^-3 m^3), and P = 110 kPa = 110 x 10^3 Pa (since 1 kPa = 10^3 Pa). Thus, W = -110 x 10^3 Pa * 35.0 x 10^-3 m^3 = -3850 J = -3.85 kJ.

A Gas Expands from an Initial Volume of 30