An ideal Carnot thermodynamic engine operates between $285 \mathrm {~K}$ and $460 \mathrm {~K} \text {. }$ What is its efficiency?

Question

Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by $1 - \frac{T_{\text{cold}}}{T_{\text{hot}}}$, where $T_{\text{cold}}$ and $T_{\text{hot}}$ are the temperatures of the cold and hot reservoirs, respectively, in Kelvin. Thus, the efficiency is $1 - \frac{285}{460} = 0.38$.

An Ideal Carnot Thermodynamic Engine Operates Between 285 K285 \mathrm {~K}285 K And 460 K. 460 \mathrm {~K} \text {. }460 K.

An Ideal Carnot Thermodynamic Engine Operates Between $285 \mathrm {~K}$ And $460 \mathrm {~K} \text {. }$