When 0.50 kg of water at 0°C freezes,what is the change in entropy of the water? The latent heat of fusion of water is 33,400 J/kg.

Question

Quizplus · Accepted Answer

The change in entropy of the water during the freezing process can be calculated using the formula:

ΔS = Q / T

where ΔS is the change in entropy, Q is the heat transferred, and T is the temperature at which the heat transfer occurs.

In this case, Q is the latent heat of fusion of water, which is 33,400 J/kg, and the temperature is 0°C = 273 K.

Therefore, ΔS = 33,400 J/kg / 273 K = 122.32 J/K

However, since the water is going from a liquid state to a solid state, the entropy is decreasing. Therefore, the change in entropy is negative.

Thus, the best choice is C, -610 J/K.

When 050 Kg of Water at 0°C Freezes,what Is the Change