A uniform electric field has the strength of $7.0 \mathrm {~N} / \mathrm { C }$ What is the electric energy density of this field? (ε₀ = 8.85 × 10^-12C²/N ∙ m²)

Question

Quizplus · Accepted Answer

The electric energy density $u$ in a uniform electric field $E$ is given by the formula $u = \frac{1}{2} \epsilon_0 E^2$, where $\epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2$ is the permittivity of free space, and $E = 7.0 \, \text{N}/\text{C}$ is the electric field strength. Substituting the given values, we get $u = \frac{1}{2} \times 8.85 \times 10^{-12} \times (7.0)^2 = 2.2 \times 10^{-10} \, \text{J}/\text{m}^3$.

A Uniform Electric Field Has the Strength Of 7.0 N/C7.0 \mathrm {~N} / \mathrm { C }7.0 N/C

A Uniform Electric Field Has the Strength Of $7.0 \mathrm {~N} / \mathrm { C }$