If a quantity you calculated has units of $\frac { \mathrm { kg } \cdot \mathrm { m } ^ { 3 } } { \mathrm {~s} \cdot \mathrm { C } ^ { 2 } }$ what is that quantity?
A)potential
B)resistivity
C)resistance
D)capacitance
E)current

Question

Quizplus · Accepted Answer

The units given represent the units of resistivity, which is defined as the resistance of a material per unit length and cross-sectional area. The units of resistivity are given as kg·m^3·s^2/C^2, which can be rewritten using the definitions of the base units as kg·m^3·s^-3·A^2. This is the same as the units of resistance (kg·m^2·s^-3·A^-2), except for the additional factor of length (m) in the numerator. Therefore, the quantity calculated must be resistivity.

If a Quantity You Calculated Has Units Of kg⋅m3 s⋅C2\frac { \mathrm { kg } \cdot \mathrm { m } ^ { 3 } } { \mathrm {~s} \cdot \mathrm { C } ^ { 2 } } s⋅C2kg⋅m3​

If a Quantity You Calculated Has Units Of $\frac { \mathrm { kg } \cdot \mathrm { m } ^ { 3 } } { \mathrm {~s} \cdot \mathrm { C } ^ { 2 } }$