If 3.0 × 10¹⁵ electrons flow through a section of a wire of diameter 2.0 mm in 4.0 s,what is the current through the wire? (e = 1.60 × 10^-19C) A)0.12 mA B)0.24 mA C)7.5 × 10⁷ A D)7.5 × 10¹⁴ A

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Quizplus · Accepted Answer

The current is given by the equation I = nAqv/t, where n is the number of electrons, A is the cross-sectional area of the wire, q is the charge of an electron, v is the drift velocity of the electrons, and t is the time. In this problem, we are given n = 3.0 × 10^15, A = π(1.0 × 10^-3 m)^2 = 3.14 × 10^-6 m^2, q = 1.60 × 10^-19 C, and t = 4.0 s. We can solve for v by rearranging the equation to v = It/nAq. Substituting the given values, we get v = (0.12 × 10^-3 A)(4.0 s)/(3.0 × 10^15 electrons)(3.14 × 10^-6 m^2)(1.60 × 10^-19 C) = 2.4 × 10^-4 m/s. The current is then given by I = nAqv/t = (3.0 × 10^15 electrons)(3.14 × 10^-6 m^2)(2.4 × 10^-4 m/s)/(4.0 s) = 0.12 mA.

If 30 × 1015 Electrons Flow Through a Section of a a Wire

If 30 × 10¹⁵ Electrons Flow Through a Section of a a Wire