A battery you buy at the store has an internal emf of 3.0 V.If it has an internal resistance of $14.0 \Omega$ what current will this battery put out if it is short-circuited?
A)0.21 A
B)42 A
C)4.7 A
D)130 A

Question

Quizplus · Accepted Answer

The current can be calculated using Ohm's Law, $I = \frac{V}{R}$, where $V = 3.0 V$ is the emf of the battery and $R = 14.0 \Omega$ is the internal resistance. Thus, $I = \frac{3.0 V}{14.0 \Omega} = 0.21 A$.

A Battery You Buy at the Store Has an Internal 14.0Ω14.0 \Omega14.0Ω

A Battery You Buy at the Store Has an Internal $14.0 \Omega$