A doubly charged ion with speed 6.9 × 10⁶ m/s enters a uniform 0.80-T magnetic field,traveling perpendicular to the $\vec { B }$ field.Once in the field,it moves in a circular arc of radius 30 cm.What is the mass of this ion? (e = 1.60 × 10^-19 C)

Question

Quizplus · Accepted Answer

The correct answer is A because the mass of the ion can be calculated using the formula: m = qBr / v, where q is the charge of the ion, B is the magnetic field strength, r is the radius of the circular arc, and v is the speed of the ion. Plugging in the given values, we get: m = (2 * 1.60 × 10^-19 C) * (0.80 T) * (0.30 m) / (6.9 × 10^6 m/s) = 11 × 10^-27 kg.

A Doubly Charged Ion with Speed 6 B⃗\vec { B }B

A Doubly Charged Ion with Speed 6 $\vec { B }$