A straight wire carries a current of 10 A at an angle of 30° with respect to the direction of a uniform 0.30-T $\vec { B }$ field.Find the magnitude of the magnetic force exerted on a 0.50-m length of the wire.

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Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by $F = I L B \sin(\theta)$, where $I$ is the current, $L$ is the length of the wire, $B$ is the magnetic field strength, and $\theta$ is the angle between the wire and the magnetic field direction. Plugging in the given values: $F = 10 \, \text{A} \times 0.50 \, \text{m} \times 0.30 \, \text{T} \times \sin(30^\circ) = 0.75 \, \text{N}$.

A Straight Wire Carries a Current of 10 a at an Angle