What is the force per meter on a straight wire carrying 5.0 A when it is placed in a magnetic field of 0.020 T so that the wire makes an angle of 27° with respect to the $\vec { B }$ field lines.

Question

Quizplus · Accepted Answer

The force per meter ($F/L$) on a straight wire carrying a current $I$ in a magnetic field $B$ is given by $F/L = I B \sin(\theta)$, where $\theta$ is the angle between the wire and the magnetic field. Substituting the given values: $F/L = 5.0 \, \text{A} \times 0.020 \, \text{T} \times \sin(27^\circ) \approx 0.045 \, \text{N/m}$.

What Is the Force Per Meter on a Straight Wire B⃗\vec { B }B

What Is the Force Per Meter on a Straight Wire $\vec { B }$