The $\vec { B }$ field due to the current through a long,straight wire is 8.0 μT at a distance of 4.0 cm from the center of the wire.What is the current in the wire? (μ₀ = 4π × 10^-7 T ∙ m/A)

Question

Quizplus · Accepted Answer

The magnetic field $\vec{B}$ due to a long, straight wire is given by $B = \frac{\mu_0 I}{2\pi r}$. Solving for $I$, we have $I = \frac{B \cdot 2\pi r}{\mu_0}$. Substituting $B = 8.0 \times 10^{-6} \, \text{T}$, $r = 0.04 \, \text{m}$, and $\mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A}$, we find $I = 1.6 \, \text{A}$.

The B⃗\vec { B }B Field Due to the Current Through a Long,straight Wire Is

The $\vec { B }$ Field Due to the Current Through a Long,straight Wire Is