An ac generator consisting of a coil with N turns rotating at angular speed ω in an external magnetic field B produces a maximum emf ε₀.If you now decrease the number of turns in the coil to N/2 and at the same time cause it to rotate twice as fast,what will be the new maximum emf if you do not change any of the other quantities? A)4ε₀ B)2ε₀ C)ε₀ D)ε₀/2 E)ε₀/4

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Quizplus · Accepted Answer

The maximum emf (ε) generated by an AC generator is given by ε = NABω, where N is the number of turns, A is the area of the coil, B is the magnetic field strength, and ω is the angular velocity. If N is halved and ω is doubled, the new emf will be (N/2)AB(2ω) = NABω, which is the same as the original emf.

An Ac Generator Consisting of a Coil with N Turns