An ac generator contains 80 flat rectangular loops of wire,each of which is 12 cm long and 8 cm wide.The loops rotate at 1200 rpm about an axis through the center and parallel to the long side.If the $\vec { B }$ field in which the loop rotates is uniform,has magnitude 0.30 T,and is perpendicular to the axis of rotation,what will be the maximum output voltage of this generator?
A)20 V
B)27 V
C)29 V
D)35 V

Question

Quizplus · Accepted Answer

The maximum output voltage of an AC generator is given by:$$V_{max} = NBl\omega$$where:* N is the number of loops* B is the magnetic field strength* l is the length of each loop* \omega is the angular velocityIn this problem, we have:* N = 80* B = 0.30 T* l = 12 cm = 0.12 m* \omega = 1200 rpm = 125.66 rad/sPlugging these values into the equation, we get:$$V_{max} = (80)(0.30 T)(0.12 m)(125.66 rad/s) = 29 V$$Therefore, the maximum output voltage of this generator is 29 V.

An Ac Generator Contains 80 Flat Rectangular Loops of Wire,each B⃗\vec { B }B

An Ac Generator Contains 80 Flat Rectangular Loops of Wire,each $\vec { B }$