If both the mass of a simple pendulum and its length are doubled,the period will

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Quizplus · Accepted Answer

The period of a simple pendulum is given by $T = 2\pi\sqrt{\frac{L}{g}}$, where $L$ is the length of the pendulum and $g$ is the acceleration due to gravity. Doubling the mass does not affect the period since the mass does not appear in the formula. Doubling the length $L$ results in the period being multiplied by $\sqrt{2}$, since $T' = 2\pi\sqrt{\frac{2L}{g}} = \sqrt{2} \cdot 2\pi\sqrt{\frac{L}{g}} = \sqrt{2} \cdot T$.

If Both the Mass of a Simple Pendulum and Its 2\sqrt { 2 }2​

If Both the Mass of a Simple Pendulum and Its $\sqrt { 2 }$