The intensity at a distance of 6.0 m from a source that is radiating equally in all directions is 6.0 × 10^-10 W/m².What is the power emitted by the source? A)2.1 × 10^-8 W B)2.7 × 10^-7 W C)2.1 × 10^-6 W D)2.7 × 10^-5 W

Question

Quizplus · Accepted Answer

The intensity (I) of the source at a distance (r) can be calculated using the inverse square law:

I = P/4πr^2

where P is the power emitted by the source.

Rearranging the equation, we get:

P = I * 4πr^2

Substituting the given values, we get:

P = (6.0 × 10^-10) * 4π(6.0)^2

P = 2.7 × 10^-7 W

Therefore, the power emitted by the source is 2.7 × 10^-7 W, which is option B.

The Intensity at a Distance of 6