The intensity at a distance of 6.0 m from a source that is radiating equally in all directions is 6.0 × 10^-10 W/m².What is the intensity level in dB? The threshold of human hearing is 1.0 × 10^-12 W/m². A)18 dB B)23 dB C)28 dB D)32 dB

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Quizplus · Accepted Answer

The intensity level in decibels (dB) can be calculated using the formula: $ \text{Level (dB)} = 10 \log_{10} \left( \frac{I}{I_0} \right) $, where $I$ is the intensity of the sound and $I_0$ is the reference intensity (threshold of human hearing), which is $1.0 \times 10^{-12} \, \text{W/m}^2$. Substituting $I = 6.0 \times 10^{-10} \, \text{W/m}^2$ and $I_0 = 1.0 \times 10^{-12} \, \text{W/m}^2$ into the formula gives $ \text{Level} = 10 \log_{10} (600) $, which calculates to approximately 28 dB.

The Intensity at a Distance of 6