A 4.0-cm-tall object is placed 50.0 cm from a concave lens having a focal length of magnitude 25.0 cm.What is the nature and location of the image?

Question

Quizplus · Accepted Answer

Concave lenses always produce virtual, upright, and smaller images. Using the lens equation 1/f = 1/v - 1/u, where f = -25.0 cm (negative for concave lens), and u = -50.0 cm (negative for the object's position on the same side as the incoming light), we find v. The magnification equation, m = v/u = h'/h, where h' is the image height and h is the object height, helps determine the image height. Solving these equations gives a virtual image 1.3 cm tall, 16.7 cm on the same side as the object.

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