The speed of light in a material is $0.41 \mathrm { c }$ What is the critical angle of a light ray at the interface between the material and a vacuum?

Question

Quizplus · Accepted Answer

The critical angle can be found using Snell's Law: $ n_1 \sin(\theta_c) = n_2 \sin(90^\circ) $. Here, $ n_1 = \frac{c}{0.41c} \approx 2.44 $ and $ n_2 = 1 $. Solving for $\theta_c$, $\sin(\theta_c) = \frac{1}{2.44} \approx 0.41$, which gives $\theta_c \approx 24^\circ$.

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The Speed of Light in a Material Is $0.41 \mathrm { c }$