In a two-slit experiment,the slit separation is 3.00 × $10^{ - 5}$ m.The interference pattern is created on a screen that is 2.00 m away from the slits.If the 7th bright fringe on the screen is 10.0 cm away from the central fringe,what is the wavelength of the light?

Question

Quizplus · Accepted Answer

The distance between the central fringe and the 7th bright fringe is given as:
y = (7λD)/d, where λ is the wavelength, D is the distance from the slits to the screen, and d is the slit separation. 
Plugging in the given values, we have:
0.1 m = (7λ)(2 m)/(3x10^-5 m)
Solving for λ, we get:
λ = 214 nm (rounded to 3 significant figures) 
Therefore, the correct choice is C.

In a Two-Slit Experiment,the Slit Separation Is 3 10−510^{ - 5}10−5

In a Two-Slit Experiment,the Slit Separation Is 3 $10^{ - 5}$