At a particular point and instant,the $\vec { E }$ field component of an electromagnetic wave is 15.0 μT.What is the magnetic energy density of this wave at that point and instant? (c = 3.00 × 10⁸ m/s,μ₀ = 4π × 10^-7 T ∙ m/A,ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A)2.26 × 10^-4 J/m³ B)8.95 × 10^-5 J/m³ C)1.79 × 10^-4 J/m³ D)4.47 × 10^-4 J/m³ E)9.72 × 10^-5 J/m³

Question

Quizplus · Accepted Answer

The magnetic energy density $u_B$ of an electromagnetic wave can be calculated using the formula $u_B = \frac{1}{2} \mu_0 B^2$, where $B$ is the magnetic field strength and $\mu_0$ is the permeability of free space. Given $B = 15.0 \, \mu T = 15.0 \times 10^{-6} \, T$ and $\mu_0 = 4\pi \times 10^{-7} \, T \cdot m/A$, substituting these values gives $u_B = \frac{1}{2} \times 4\pi \times 10^{-7} \times (15.0 \times 10^{-6})^2 = 8.95 \times 10^{-5} \, J/m^3$.

At a Particular Point and Instant,the E⃗\vec { E }E Field Component of an Electromagnetic Wave Is 15

At a Particular Point and Instant,the $\vec { E }$ Field Component of an Electromagnetic Wave Is 15