An 800-kHz sinusoidal radio signal is detected at a point 6.6 km from the transmitter tower.The $\vec { E }$ field amplitude of the signal at that point is 0.780 V/m.Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed.What is the amplitude of the $\vec { B }$ field of the signal at that point? (ε₀ = 8.85 × 10^-12 C²/N ∙ m²,c = 3.0 × 10⁸ m/s,μ₀ = 4π × 10^-7 T ∙ m/A) A)2.6 nT B)2.1 nT C)1.6 nT D)3.1 nT E)3.6 nT

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The amplitude of the magnetic field of an electromagnetic wave is given by:$$B = \frac{E}{c}$$where:* B is the magnetic field amplitude in teslas (T)* E is the electric field amplitude in volts per meter (V/m)* c is the speed of light in meters per second (m/s)In this problem, we are given:* E = 0.780 V/m* c = 3.0 × 10^8 m/sPlugging these values into the equation above, we get:$$B = \frac{0.780 V/m}{3.0 × 10^8 m/s} = 2.6 × 10^{-9} T = 2.6 nT$$Therefore, the amplitude of the magnetic field of the signal at that point is 2.6 nT.

An 800-KHz Sinusoidal Radio Signal Is Detected at a Point E⃗\vec { E }E

An 800-KHz Sinusoidal Radio Signal Is Detected at a Point $\vec { E }$