An astronaut on a spaceship moving at 0.927c says that the trip between two stationary stars took $4.26 \mathrm { y }$ How long does this journey appear to take to someone in the rest frame of the two stars?

Question

Quizplus · Accepted Answer

The time dilation formula, $t = \frac{t_0}{\sqrt{1 - v^2/c^2}}$, where $t_0$ is the proper time (time measured by the moving observer, 4.26 years), $v$ is the velocity of the spaceship (0.927c), and $c$ is the speed of light, can be used to calculate the time observed in the rest frame. Plugging in the values, we find the time to be approximately 11.4 years.

An Astronaut on a Spaceship Moving at 0 4.26y4.26 \mathrm { y }4.26y

An Astronaut on a Spaceship Moving at 0 $4.26 \mathrm { y }$