In a transition from one vibrational state to another,a molecule emits a photon of wavelength 5.56 µm.What is the energy difference between these two states? (c = 3.00 × 10⁸ m/s,h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19J) A)0.223 eV B)2.23 MeV C)13.6 eV D)13.6 MeV E)0.223 MeV

Question

Quizplus · Accepted Answer

We can use the equation:

E = hc/λ

where E is the energy difference, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

Plugging in the given values, we get:

E = (6.626 × 10^-34 J ∙ s)(3.00 × 10^8 m/s)/(5.56 × 10^-6 m)

Simplifying, we get:

E = 3.57 × 10^-20 J

Finally, we can convert this to electron volts (eV) using the conversion factor given:

E = (3.57 × 10^-20 J)(1 eV/1.60 × 10^-19 J)

Simplifying again, we get:

E = 0.223 eV

Therefore, the answer is choice A.

In a Transition from One Vibrational State to Another,a Molecule