What frequency must a photon have to change the energy of a hydrogen atom from the n = 2 to the n = 4 state? (h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19J) A)3.06 × 10¹⁴ Hz B)6.16 × 10¹⁴ Hz C)4.11 × 10¹⁴ Hz D)5.20 × 10¹⁴ Hz E)9.24 × 10¹⁴ Hz

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Quizplus · Accepted Answer

The energy difference between the n=2 and n=4 states in a hydrogen atom is 2.55 eV. Using E = hf, where E is the energy in joules, h is Planck's constant, and f is the frequency, the frequency is calculated as 6.16 × 10^14 Hz.

What Frequency Must a Photon Have to Change the Energy