The following masses are known: $\begin{array} { l } 1 \ 0 \end{array}$ n 1.008665 u $\begin{array} { l } 1 \ 1 \end{array}$ H 1.007825 u $^{226} _{88} Ra$ 226.025403 u What is the binding energy of $^{226} _{88} Ra$? (1 u = 931.5 MeV/c²)

Question

Quizplus · Accepted Answer

The binding energy is the difference between the mass of the individual nucleons and the mass of the nucleus. The mass of the individual nucleons is 88(1.007825 u) + 138(1.008665 u) = 226.98977 u. The mass of the nucleus is 226.025403 u. Therefore, the binding energy is (226.98977 u - 226.025403 u) * 931.5 MeV/c² = 1700 MeV.

The Following Masses Are Known 10\begin{array} { l } 1 \\0\end{array}10​

The Following Masses Are Known $\begin{array} { l } 1 \\0\end{array}$