Rutherfordium-261 has a half-life of 1.08 min.What is the decay constant of rutherfordium-261 in terms of seconds?

Name: Rutherfordium-261 has a half-life of 1.08 min.What is the decay constant of rutherfordium-261 in terms of seconds?
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Quizplus · Accepted Answer

The decay constant ($\lambda$) can be calculated using the formula $\lambda = \frac{\ln(2)}{t_{1/2}}$, where $t_{1/2}$ is the half-life. Converting 1.08 minutes to seconds gives 64.8 seconds. Thus, $\lambda = \frac{0.693}{64.8} = 0.0107 s^{-1}$.

Rutherfordium-261 Has a Half-Life of 1