Consider the nuclear reaction ${}^{14}_{7}$ N + ${}^{4}_{2}$ He → ${}^{14}_{8}$ O + $\begin{array} { l } 1 \ 1 \end{array}$ H.The known atomic masses are ${}^{14}_{7}$ N: 14.003074 u ${}^{4}_{2}$ He: 4.002603 u ${}^{1}_{1}$ H: 1.007825 u ${}^{17}_{8}$ O: 16.999131 u What is the Q-value (or reaction energy)of this reaction? (1 u = 931.5 MeV/c²)

Question

Quizplus · Accepted Answer

The Q-value of a nuclear reaction can be calculated using the masses of the reactants and products. The formula for the Q-value is: $$Q = (m_{reactants} - m_{products}) \times 931.5 \, \text{MeV/c}^2$$Given atomic masses are:- ${}^{14}_{7}$ N: 14.003074 u- ${}^{4}_{2}$ He: 4.002603 u- ${}^{1}_{1}$ H: 1.007825 u- ${}^{17}_{8}$ O: 16.999131 uFirst, calculate the total mass of reactants:$$m_{reactants} = 14.003074 \, u + 4.002603 \, u = 18.005677 \, u$$Then, calculate the total mass of products:$$m_{products} = 16.999131 \, u + 1.007825 \, u = 18.006956 \, u$$Now, calculate the Q-value:$$Q = (18.005677 \, u - 18.006956 \, u) \times 931.5 \, \text{MeV/c}^2 = -1.191 \, \text{MeV}$$Therefore, the Q-value of the reaction is -1.191 MeV.

Consider the Nuclear Reaction 714{}^{14}_{7}714​ N 24{}^{4}_{2}24​ He → 814{}^{14}_{8}814​ O 11\begin{array} { l } 1 \\1\end{array}11​

Consider the Nuclear Reaction ${}^{14}_{7}$ N ${}^{4}_{2}$ He → ${}^{14}_{8}$ O $\begin{array} { l } 1 \\1\end{array}$