0.68 g of sulfur combine with 1.51 g of chlorine. The empirical formula of this compound is ________.

Name: 0.68 g of sulfur combine with 1.51 g of chlorine. The empirical formula of this compound is ________.
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Question

Quizplus · Accepted Answer

To find the empirical formula, calculate the moles of each element: Moles of S = 0.68 g / 32.07 g/mol = 0.0212 mol; Moles of Cl = 1.51 g / 35.45 g/mol = 0.0426 mol. The ratio of S to Cl is approximately 1:2, so the empirical formula is SCl₂.

068 G of Sulfur Combine with 1